2x^2-5x+38=0

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Solution for 2x^2-5x+38=0 equation:


Simplifying
2x2 + -5x + 38 = 0

Reorder the terms:
38 + -5x + 2x2 = 0

Solving
38 + -5x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
19 + -2.5x + x2 = 0

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + -2.5x + -19 + x2 = 0 + -19

Reorder the terms:
19 + -19 + -2.5x + x2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -2.5x + x2 = 0 + -19
-2.5x + x2 = 0 + -19

Combine like terms: 0 + -19 = -19
-2.5x + x2 = -19

The x term is -2.5x.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5x + 1.5625 + x2 = -19 + 1.5625

Reorder the terms:
1.5625 + -2.5x + x2 = -19 + 1.5625

Combine like terms: -19 + 1.5625 = -17.4375
1.5625 + -2.5x + x2 = -17.4375

Factor a perfect square on the left side:
(x + -1.25)(x + -1.25) = -17.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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